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142045321435555 = 573599649691593
BaseRepresentation
bin100000010011000010000000…
…111011010001100110100011
3200121221101210200100212022111
4200103002000323101212203
5122104232304241414210
61222034415251420151
741630302324450246
oct4023020073214643
9617841720325274
10142045321435555
114129509a92239a
1213b214028b4657
136134a7c64a655
14271105cd9d25d
151164dd124c88a
hex813080ed19a3

142045321435555 has 16 divisors (see below), whose sum is σ = 173077840641600. Its totient is φ = 111892484740608.

The previous prime is 142045321435543. The next prime is 142045321435561. The reversal of 142045321435555 is 555534123540241.

It is a cyclic number.

It is not a de Polignac number, because 142045321435555 - 231 = 142043173951907 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142045321435499 and 142045321435508.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324627162 + ... + 325064431.

It is an arithmetic number, because the mean of its divisors is an integer number (10817365040100).

Almost surely, 2142045321435555 is an apocalyptic number.

142045321435555 is a deficient number, since it is larger than the sum of its proper divisors (31032519206045).

142045321435555 is an equidigital number, since it uses as much as digits as its factorization.

142045321435555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 649692270.

The product of its (nonzero) digits is 7200000, while the sum is 49.

Adding to 142045321435555 its reverse (555534123540241), we get a palindrome (697579444975796).

The spelling of 142045321435555 in words is "one hundred forty-two trillion, forty-five billion, three hundred twenty-one million, four hundred thirty-five thousand, five hundred fifty-five".

Divisors: 1 5 73 365 599 2995 43727 218635 649691593 3248457965 47427486289 237137431445 389165264207 1945826321035 28409064287111 142045321435555