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14210035525201 = 64199122369871
BaseRepresentation
bin1100111011001000100000…
…0111101010011001010001
31212022110120210211010210111
43032302020013222121101
53330304123043301301
650120000013201321
72664432633016405
oct316621007523121
955273523733714
1014210035525201
11458949566546a
121716000190241
137c100141b3c9
14371aab2bd105
151999803eb551
hexcec881ea651

14210035525201 has 8 divisors (see below), whose sum is σ = 14246566161408. Its totient is φ = 14173549632000.

The previous prime is 14210035525199. The next prime is 14210035525241. The reversal of 14210035525201 is 10252553001241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14210035525201 - 21 = 14210035525199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14210035525241) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10549705 + ... + 11820166.

It is an arithmetic number, because the mean of its divisors is an integer number (1780820770176).

Almost surely, 214210035525201 is an apocalyptic number.

It is an amenable number.

14210035525201 is a deficient number, since it is larger than the sum of its proper divisors (36530636207).

14210035525201 is an equidigital number, since it uses as much as digits as its factorization.

14210035525201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22371503.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 14210035525201 its reverse (10252553001241), we get a palindrome (24462588526442).

The spelling of 14210035525201 in words is "fourteen trillion, two hundred ten billion, thirty-five million, five hundred twenty-five thousand, two hundred one".

Divisors: 1 641 991 635231 22369871 14339087311 22168542161 14210035525201