142100442131 has 4 divisors (see below), whose sum is σ = 142143208152. Its totient is φ = 142057676112.

The previous prime is 142100442119. The next prime is 142100442151. The reversal of 142100442131 is 131244001241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142100442131 - 2¹⁸ = 142100179987 is a prime.

It is a super-2 number, since 2×142100442131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142100442097 and 142100442106.

It is not an unprimeable number, because it can be changed into a prime (142100442151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21378026 + ... + 21384671.

It is an arithmetic number, because the mean of its divisors is an integer number (35535802038).

Almost surely, 2^142100442131 is an apocalyptic number.

142100442131 is a deficient number, since it is larger than the sum of its proper divisors (42766021).

142100442131 is an equidigital number, since it uses as much as digits as its factorization.

142100442131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42766020.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 142100442131 its reverse (131244001241), we get a palindrome (273344443372).

The spelling of 142100442131 in words is "one hundred forty-two billion, one hundred million, four hundred forty-two thousand, one hundred thirty-one".