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14211223433 = 114572826979
BaseRepresentation
bin11010011110000111…
…00000111110001001
31100200101220221122122
431033003200332021
5213101033122213
610310055501025
71012111256201
oct151703407611
940611827578
1014211223433
116032957560
122907387775
1314562c5864
1498b57b401
15582957d08
hex34f0e0f89

14211223433 has 8 divisors (see below), whose sum is σ = 15537082080. Its totient is φ = 12891019680.

The previous prime is 14211223427. The next prime is 14211223447. The reversal of 14211223433 is 33432211241.

14211223433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14211223433 - 28 = 14211223177 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14211220433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1408463 + ... + 1418516.

It is an arithmetic number, because the mean of its divisors is an integer number (1942135260).

Almost surely, 214211223433 is an apocalyptic number.

It is an amenable number.

14211223433 is a deficient number, since it is larger than the sum of its proper divisors (1325858647).

14211223433 is a wasteful number, since it uses less digits than its factorization.

14211223433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2827447.

The product of its digits is 3456, while the sum is 26.

Adding to 14211223433 its reverse (33432211241), we get a palindrome (47643434674).

The spelling of 14211223433 in words is "fourteen billion, two hundred eleven million, two hundred twenty-three thousand, four hundred thirty-three".

Divisors: 1 11 457 5027 2826979 31096769 1291929403 14211223433