Base | Representation |
---|---|
bin | 1000010001011010011… |
… | …1011010001000001011 |
3 | 111120211010100012011011 |
4 | 2010112213122020023 |
5 | 4312022004201110 |
6 | 145141434144351 |
7 | 13160462355010 |
oct | 2042647321013 |
9 | 446733305134 |
10 | 142113350155 |
11 | 552a7310417 |
12 | 236615820b7 |
13 | 1052a67554a |
14 | 6c42191707 |
15 | 3a6b52448a |
hex | 21169da20b |
142113350155 has 8 divisors (see below), whose sum is σ = 194898308832. Its totient is φ = 97449154368.
The previous prime is 142113350123. The next prime is 142113350167. The reversal of 142113350155 is 551053311241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 142113350155 - 25 = 142113350123 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2030190682 + ... + 2030190751.
It is an arithmetic number, because the mean of its divisors is an integer number (24362288604).
Almost surely, 2142113350155 is an apocalyptic number.
142113350155 is a deficient number, since it is larger than the sum of its proper divisors (52784958677).
142113350155 is an equidigital number, since it uses as much as digits as its factorization.
142113350155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4060381445.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 142113350155 its reverse (551053311241), we get a palindrome (693166661396).
The spelling of 142113350155 in words is "one hundred forty-two billion, one hundred thirteen million, three hundred fifty thousand, one hundred fifty-five".
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