Base | Representation |
---|---|
bin | 100000010100000010000101… |
… | …000110101001110101100011 |
3 | 200122011222100202002000020212 |
4 | 200110002011012221311203 |
5 | 122111344144404112003 |
6 | 1222130153222524335 |
7 | 41635256103234035 |
oct | 4024020506516543 |
9 | 618158322060225 |
10 | 142114111004003 |
11 | 4131128a833306 |
12 | 13b328002966ab |
13 | 613b3c308a6c8 |
14 | 2714506d2bc55 |
15 | 1166aaa461dd8 |
hex | 8140851a9d63 |
142114111004003 has 8 divisors (see below), whose sum is σ = 142986365715648. Its totient is φ = 141241861036584.
The previous prime is 142114111003981. The next prime is 142114111004011. The reversal of 142114111004003 is 300400111411241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142114111004003 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 142114111004003.
It is not an unprimeable number, because it can be changed into a prime (142114111004023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73167776 + ... + 75084962.
It is an arithmetic number, because the mean of its divisors is an integer number (17873295714456).
Almost surely, 2142114111004003 is an apocalyptic number.
142114111004003 is a deficient number, since it is larger than the sum of its proper divisors (872254711645).
142114111004003 is a wasteful number, since it uses less digits than its factorization.
142114111004003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2372113.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 142114111004003 its reverse (300400111411241), we get a palindrome (442514222415244).
The spelling of 142114111004003 in words is "one hundred forty-two trillion, one hundred fourteen billion, one hundred eleven million, four thousand, three".
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