142114113131 has 4 divisors (see below), whose sum is σ = 142268754000. Its totient is φ = 141959472264.

The previous prime is 142114113101. The next prime is 142114113137. The reversal of 142114113131 is 131311411241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142114113131 - 2²² = 142109918827 is a prime.

It is a super-3 number, since 3×142114113131³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142114113097 and 142114113106.

It is not an unprimeable number, because it can be changed into a prime (142114113137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77319056 + ... + 77320893.

It is an arithmetic number, because the mean of its divisors is an integer number (35567188500).

Almost surely, 2^142114113131 is an apocalyptic number.

142114113131 is a deficient number, since it is larger than the sum of its proper divisors (154640869).

142114113131 is an equidigital number, since it uses as much as digits as its factorization.

142114113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154640868.

The product of its digits is 288, while the sum is 23.

Adding to 142114113131 its reverse (131311411241), we get a palindrome (273425524372).

The spelling of 142114113131 in words is "one hundred forty-two billion, one hundred fourteen million, one hundred thirteen thousand, one hundred thirty-one".