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14212034223441 = 34737344741147
BaseRepresentation
bin1100111011001111111101…
…0000000101110101010001
31212022122202002201112100020
43032303333100011311101
53330322221230122231
650120530212214053
72664533312460105
oct316637720056521
955278662645306
1014212034223441
11458a3208a2a9a
12171647960a329
137c125c52b0a2
14371c1a919905
15199a4ab03396
hexcecff405d51

14212034223441 has 4 divisors (see below), whose sum is σ = 18949378964592. Its totient is φ = 9474689482292.

The previous prime is 14212034223403. The next prime is 14212034223487. The reversal of 14212034223441 is 14432243021241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14212034223441 - 210 = 14212034222417 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14212034223341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2368672370571 + ... + 2368672370576.

It is an arithmetic number, because the mean of its divisors is an integer number (4737344741148).

Almost surely, 214212034223441 is an apocalyptic number.

It is an amenable number.

14212034223441 is a deficient number, since it is larger than the sum of its proper divisors (4737344741151).

14212034223441 is an equidigital number, since it uses as much as digits as its factorization.

14212034223441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4737344741150.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 14212034223441 its reverse (14432243021241), we get a palindrome (28644277244682).

The spelling of 14212034223441 in words is "fourteen trillion, two hundred twelve billion, thirty-four million, two hundred twenty-three thousand, four hundred forty-one".

Divisors: 1 3 4737344741147 14212034223441