Base | Representation |
---|---|
bin | 10100101011100110111… |
… | …010001100011000101011 |
3 | 12000212101210102011001011 |
4 | 110223212322030120223 |
5 | 141241121041104233 |
6 | 3004521335404351 |
7 | 204451663032430 |
oct | 24534672143053 |
9 | 5025353364034 |
10 | 1421213222443 |
11 | 4a88078a4293 |
12 | 1ab5355236b7 |
13 | a40347554c1 |
14 | 4cb03aa3b87 |
15 | 26e806790cd |
hex | 14ae6e8c62b |
1421213222443 has 4 divisors (see below), whose sum is σ = 1624243682800. Its totient is φ = 1218182762088.
The previous prime is 1421213222381. The next prime is 1421213222479. The reversal of 1421213222443 is 3442223121241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1421213222443 - 213 = 1421213214251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1421213202443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101515230168 + ... + 101515230181.
It is an arithmetic number, because the mean of its divisors is an integer number (406060920700).
Almost surely, 21421213222443 is an apocalyptic number.
1421213222443 is a deficient number, since it is larger than the sum of its proper divisors (203030460357).
1421213222443 is an equidigital number, since it uses as much as digits as its factorization.
1421213222443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 203030460356.
The product of its digits is 18432, while the sum is 31.
Adding to 1421213222443 its reverse (3442223121241), we get a palindrome (4863436343684).
The spelling of 1421213222443 in words is "one trillion, four hundred twenty-one billion, two hundred thirteen million, two hundred twenty-two thousand, four hundred forty-three".
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