Base | Representation |
---|---|
bin | 1100111011010001010110… |
… | …1010011111101110100011 |
3 | 1212022200201022021100120201 |
4 | 3032310111222133232203 |
5 | 3330324004010302003 |
6 | 50121031403450031 |
7 | 2664545526550006 |
oct | 316642552375643 |
9 | 55280638240521 |
10 | 14212410244003 |
11 | 458a4a407a894 |
12 | 1716563526917 |
13 | 7c12bc3c4b6a |
14 | 371c5483b53d |
15 | 199a6db2bb1d |
hex | ced15a9fba3 |
14212410244003 has 4 divisors (see below), whose sum is σ = 14212594560528. Its totient is φ = 14212225927480.
The previous prime is 14212410243947. The next prime is 14212410244031. The reversal of 14212410244003 is 30044201421241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14212410244003 - 221 = 14212408146851 is a prime.
It is a super-4 number, since 4×142124102440034 (a number of 54 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14212410244093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92042551 + ... + 92196832.
It is an arithmetic number, because the mean of its divisors is an integer number (3553148640132).
Almost surely, 214212410244003 is an apocalyptic number.
14212410244003 is a deficient number, since it is larger than the sum of its proper divisors (184316525).
14212410244003 is an equidigital number, since it uses as much as digits as its factorization.
14212410244003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 184316524.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 14212410244003 its reverse (30044201421241), we get a palindrome (44256611665244).
The spelling of 14212410244003 in words is "fourteen trillion, two hundred twelve billion, four hundred ten million, two hundred forty-four thousand, three".
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