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1421300031241 = 1738671194747
BaseRepresentation
bin10100101011101100000…
…101010101111100001001
312000212121211202111022211
4110223230011111330021
5141241310301444431
63004534120145121
7204454065634336
oct24535405257411
95025554674284
101421300031241
114a88518a5aa2
121ab55a6081a1
13a404972aa5c
144cb1141d98d
1526e880c52b1
hex14aec155f09

1421300031241 has 8 divisors (see below), whose sum is σ = 1429547212224. Its totient is φ = 1413053213520.

The previous prime is 1421300031211. The next prime is 1421300031269.

1421300031241 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1421300031241 - 227 = 1421165813513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1421300031211) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14953630 + ... + 15048376.

It is an arithmetic number, because the mean of its divisors is an integer number (178693401528).

Almost surely, 21421300031241 is an apocalyptic number.

It is an amenable number.

1421300031241 is a deficient number, since it is larger than the sum of its proper divisors (8247180983).

1421300031241 is an equidigital number, since it uses as much as digits as its factorization.

1421300031241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181631.

The product of its (nonzero) digits is 576, while the sum is 22.

It can be divided in two parts, 14213000 and 31241, that added together give a palindrome (14244241).

The spelling of 1421300031241 in words is "one trillion, four hundred twenty-one billion, three hundred million, thirty-one thousand, two hundred forty-one".

Divisors: 1 173 86711 94747 15001003 16391231 8215607117 1421300031241