Base | Representation |
---|---|
bin | 11010011110010100… |
… | …11110111100110011 |
3 | 1100200112100202110022 |
4 | 31033022132330303 |
5 | 213102020101123 |
6 | 10310202554055 |
7 | 1012132635014 |
oct | 151712367463 |
9 | 40615322408 |
10 | 14213050163 |
11 | 6033994a54 |
12 | 2907b0892b |
13 | 14567b5170 |
14 | 98b8d500b |
15 | 582bb91c8 |
hex | 34f29ef33 |
14213050163 has 4 divisors (see below), whose sum is σ = 15306361728. Its totient is φ = 13119738600.
The previous prime is 14213050157. The next prime is 14213050213. The reversal of 14213050163 is 36105031241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 36105031241 = 23 ⋅1569783967.
It is a cyclic number.
It is not a de Polignac number, because 14213050163 - 24 = 14213050147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14213050153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546655763 + ... + 546655788.
It is an arithmetic number, because the mean of its divisors is an integer number (3826590432).
Almost surely, 214213050163 is an apocalyptic number.
14213050163 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
14213050163 is a deficient number, since it is larger than the sum of its proper divisors (1093311565).
14213050163 is a wasteful number, since it uses less digits than its factorization.
14213050163 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1093311564.
The product of its (nonzero) digits is 2160, while the sum is 26.
The spelling of 14213050163 in words is "fourteen billion, two hundred thirteen million, fifty thousand, one hundred sixty-three".
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