14213104000003 has 4 divisors (see below), whose sum is σ = 14213129713848. Its totient is φ = 14213078286160.

The previous prime is 14213103999931. The next prime is 14213104000021. The reversal of 14213104000003 is 30000040131241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14213104000003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14213104001003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12009178 + ... + 13139503.

It is an arithmetic number, because the mean of its divisors is an integer number (3553282428462).

Almost surely, 2^{14213104000003} is an apocalyptic number.

14213104000003 is a deficient number, since it is larger than the sum of its proper divisors (25713845).

14213104000003 is an equidigital number, since it uses as much as digits as its factorization.

14213104000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25713844.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 14213104000003 its reverse (30000040131241), we get a palindrome (44213144131244).

The spelling of 14213104000003 in words is "fourteen trillion, two hundred thirteen billion, one hundred four million, three", and thus it is an aban number.