Base | Representation |
---|---|
bin | 11010011110011101… |
… | …11010111000001011 |
3 | 1100200121112211202012 |
4 | 31033032322320023 |
5 | 213102314310011 |
6 | 10310243530135 |
7 | 1012145550416 |
oct | 151716727013 |
9 | 40617484665 |
10 | 14214213131 |
11 | 6034609788 |
12 | 290838994b |
13 | 1456b01601 |
14 | 98bb18b7d |
15 | 582d48a8b |
hex | 34f3bae0b |
14214213131 has 4 divisors (see below), whose sum is σ = 14214471264. Its totient is φ = 14213955000.
The previous prime is 14214213121. The next prime is 14214213157. The reversal of 14214213131 is 13131241241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14214213131 - 26 = 14214213067 is a prime.
It is a super-2 number, since 2×142142131312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14214213097 and 14214213106.
It is not an unprimeable number, because it can be changed into a prime (14214213121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9620 + ... + 168881.
It is an arithmetic number, because the mean of its divisors is an integer number (3553617816).
Almost surely, 214214213131 is an apocalyptic number.
14214213131 is a deficient number, since it is larger than the sum of its proper divisors (258133).
14214213131 is an equidigital number, since it uses as much as digits as its factorization.
14214213131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258132.
The product of its digits is 576, while the sum is 23.
Adding to 14214213131 its reverse (13131241241), we get a palindrome (27345454372).
The spelling of 14214213131 in words is "fourteen billion, two hundred fourteen million, two hundred thirteen thousand, one hundred thirty-one".
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