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142153311035 = 540170899407
BaseRepresentation
bin1000010001100011111…
…1110110001100111011
3111120220220112102011202
42010120333312030323
54312112221423120
6145145422444415
713161456131021
oct2043077661473
9446826472152
10142153311035
115531792463a
1223672a3370b
1310535a27338
146c475d4711
153a6ecb9875
hex2118ff633b

142153311035 has 8 divisors (see below), whose sum is σ = 171009372096. Its totient is φ = 113439049600.

The previous prime is 142153311031. The next prime is 142153311037. The reversal of 142153311035 is 530113351241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 142153311035 - 22 = 142153311031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142153310989 and 142153311007.

It is not an unprimeable number, because it can be changed into a prime (142153311031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35447699 + ... + 35451708.

It is an arithmetic number, because the mean of its divisors is an integer number (21376171512).

Almost surely, 2142153311035 is an apocalyptic number.

142153311035 is a deficient number, since it is larger than the sum of its proper divisors (28856061061).

142153311035 is an equidigital number, since it uses as much as digits as its factorization.

142153311035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70899813.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 142153311035 its reverse (530113351241), we get a palindrome (672266662276).

The spelling of 142153311035 in words is "one hundred forty-two billion, one hundred fifty-three million, three hundred eleven thousand, thirty-five".

Divisors: 1 5 401 2005 70899407 354497035 28430662207 142153311035