Base | Representation |
---|---|
bin | 1100111011101101101001… |
… | …0010111000110110110011 |
3 | 1212100102022112111221201202 |
4 | 3032323122102320312303 |
5 | 3330440032024244243 |
6 | 50124325115121415 |
7 | 2665234646550641 |
oct | 316733222706663 |
9 | 55312275457652 |
10 | 14220004134323 |
11 | 4592740689aa9 |
12 | 1717b2274326b |
13 | 7c1c2c7677a0 |
14 | 3723751d0191 |
15 | 199d656584b8 |
hex | ceeda4b8db3 |
14220004134323 has 16 divisors (see below), whose sum is σ = 15351513660000. Its totient is φ = 13093888604160.
The previous prime is 14220004134319. The next prime is 14220004134373. The reversal of 14220004134323 is 32343140002241.
It is not a de Polignac number, because 14220004134323 - 22 = 14220004134319 is a prime.
It is a super-3 number, since 3×142200041343233 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14220004134373) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25105028 + ... + 25665198.
It is an arithmetic number, because the mean of its divisors is an integer number (959469603750).
Almost surely, 214220004134323 is an apocalyptic number.
14220004134323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
14220004134323 is a deficient number, since it is larger than the sum of its proper divisors (1131509525677).
14220004134323 is a wasteful number, since it uses less digits than its factorization.
14220004134323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 564982.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 14220004134323 its reverse (32343140002241), we get a palindrome (46563144136564).
The spelling of 14220004134323 in words is "fourteen trillion, two hundred twenty billion, four million, one hundred thirty-four thousand, three hundred twenty-three".
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