Search a number
-
+
1422115 = 5284423
BaseRepresentation
bin101011011001100100011
32200020202221
411123030203
5331001430
650251511
715042052
oct5331443
92606687
101422115
11891502
12586b97
133aa3b6
14290399
151d157a
hex15b323

1422115 has 4 divisors (see below), whose sum is σ = 1706544. Its totient is φ = 1137688.

The previous prime is 1422107. The next prime is 1422119. The reversal of 1422115 is 5112241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5112241 = 31164911.

It is a cyclic number.

It is not a de Polignac number, because 1422115 - 23 = 1422107 is a prime.

It is a super-2 number, since 2×14221152 = 4044822146450, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1422119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142207 + ... + 142216.

It is an arithmetic number, because the mean of its divisors is an integer number (426636).

21422115 is an apocalyptic number.

1422115 is a deficient number, since it is larger than the sum of its proper divisors (284429).

1422115 is an equidigital number, since it uses as much as digits as its factorization.

1422115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 284428.

The product of its digits is 80, while the sum is 16.

The square root of 1422115 is about 1192.5246328693. The cubic root of 1422115 is about 112.4548625507.

Adding to 1422115 its reverse (5112241), we get a palindrome (6534356).

The spelling of 1422115 in words is "one million, four hundred twenty-two thousand, one hundred fifteen".

Divisors: 1 5 284423 1422115