Base | Representation |
---|---|
bin | 11010011111011010… |
… | …00111110011100011 |
3 | 1100201011110002012111 |
4 | 31033231013303203 |
5 | 213111331133103 |
6 | 10311125340151 |
7 | 1012303054015 |
oct | 151755076343 |
9 | 40634402174 |
10 | 14222130403 |
11 | 6039027088 |
12 | 290ab67657 |
13 | 14586441a0 |
14 | 98cbba1b5 |
15 | 5838ae86d |
hex | 34fb47ce3 |
14222130403 has 4 divisors (see below), whose sum is σ = 15316140448. Its totient is φ = 13128120360.
The previous prime is 14222130361. The next prime is 14222130407. The reversal of 14222130403 is 30403122241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14222130403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14222130407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547005003 + ... + 547005028.
It is an arithmetic number, because the mean of its divisors is an integer number (3829035112).
Almost surely, 214222130403 is an apocalyptic number.
14222130403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
14222130403 is a deficient number, since it is larger than the sum of its proper divisors (1094010045).
14222130403 is a wasteful number, since it uses less digits than its factorization.
14222130403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1094010044.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 14222130403 its reverse (30403122241), we get a palindrome (44625252644).
The spelling of 14222130403 in words is "fourteen billion, two hundred twenty-two million, one hundred thirty thousand, four hundred three".
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