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14223013001 = 31458806871
BaseRepresentation
bin11010011111100000…
…11111010010001001
31100201020002220220022
431033300133102021
5213112042404001
610311200310225
71012313421131
oct151760372211
940636086808
1014223013001
11603957a1aa
12290b312375
131458892b32
1498cd69ac1
155839d611b
hex34fc1f489

14223013001 has 4 divisors (see below), whose sum is σ = 14681819904. Its totient is φ = 13764206100.

The previous prime is 14223012971. The next prime is 14223013043. The reversal of 14223013001 is 10031032241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10031032241 = 26338140807.

It is a cyclic number.

It is not a de Polignac number, because 14223013001 - 210 = 14223011977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14223013801) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229403405 + ... + 229403466.

It is an arithmetic number, because the mean of its divisors is an integer number (3670454976).

Almost surely, 214223013001 is an apocalyptic number.

It is an amenable number.

14223013001 is a deficient number, since it is larger than the sum of its proper divisors (458806903).

14223013001 is an equidigital number, since it uses as much as digits as its factorization.

14223013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 458806902.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 14223013001 its reverse (10031032241), we get a palindrome (24254045242).

The spelling of 14223013001 in words is "fourteen billion, two hundred twenty-three million, thirteen thousand, one".

Divisors: 1 31 458806871 14223013001