Base | Representation |
---|---|
bin | 1100111011111001100111… |
… | …1110100100101010111001 |
3 | 1212100201121122210121001211 |
4 | 3032332121332210222321 |
5 | 3331013123312043413 |
6 | 50130020155043121 |
7 | 2665410436342300 |
oct | 316763176445271 |
9 | 55321548717054 |
10 | 14223220034233 |
11 | 4594040a02221 |
12 | 171867b7404a1 |
13 | 7c2322ab2442 |
14 | 37259c357437 |
15 | 199ea2b4783d |
hex | cef99fa4ab9 |
14223220034233 has 72 divisors (see below), whose sum is σ = 17250880003200. Its totient is φ = 11690477809920.
The previous prime is 14223220034209. The next prime is 14223220034263. The reversal of 14223220034233 is 33243002232241.
It is not a de Polignac number, because 14223220034233 - 25 = 14223220034201 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14223220034195 and 14223220034204.
It is not an unprimeable number, because it can be changed into a prime (14223220034203) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 1477118463 + ... + 1477128091.
It is an arithmetic number, because the mean of its divisors is an integer number (239595555600).
Almost surely, 214223220034233 is an apocalyptic number.
It is an amenable number.
14223220034233 is a deficient number, since it is larger than the sum of its proper divisors (3027659968967).
14223220034233 is an equidigital number, since it uses as much as digits as its factorization.
14223220034233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10031 (or 9983 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 14223220034233 its reverse (33243002232241), we get a palindrome (47466222266474).
The spelling of 14223220034233 in words is "fourteen trillion, two hundred twenty-three billion, two hundred twenty million, thirty-four thousand, two hundred thirty-three".
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