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142233000131 = 3171123399541
BaseRepresentation
bin1000010001110110111…
…1110101100011000011
3111121010110111001001202
42010131233311203003
54312243122001011
6145201350451415
713163444360525
oct2043557654303
9447113431052
10142233000131
11553589031a2
1223695663b6b
13105493a9051
146c54019a15
153a76cab23b
hex211dbf58c3

142233000131 has 8 divisors (see below), whose sum is σ = 142809096144. Its totient is φ = 141657706080.

The previous prime is 142233000113. The next prime is 142233000167. The reversal of 142233000131 is 131000332241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142233000131 is a prime.

It is a super-2 number, since 2×1422330001312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142233000181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 156221 + ... + 555761.

It is an arithmetic number, because the mean of its divisors is an integer number (17851137018).

Almost surely, 2142233000131 is an apocalyptic number.

142233000131 is a deficient number, since it is larger than the sum of its proper divisors (576096013).

142233000131 is a wasteful number, since it uses less digits than its factorization.

142233000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400981.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 142233000131 its reverse (131000332241), we get a palindrome (273233332372).

The spelling of 142233000131 in words is "one hundred forty-two billion, two hundred thirty-three million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 317 1123 355991 399541 126654497 448684543 142233000131