1422412305353 has 4 divisors (see below), whose sum is σ = 1531828636548. Its totient is φ = 1312995974160.

The previous prime is 1422412305313. The next prime is 1422412305361. The reversal of 1422412305353 is 3535032142241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 274411488649 + 1148000816704 = 523843^2 + 1071448^2 .

It is not a de Polignac number, because 1422412305353 - 2¹⁸ = 1422412043209 is a prime.

It is a super-2 number, since 2×1422412305353² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1422412305313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54708165578 + ... + 54708165603.

It is an arithmetic number, because the mean of its divisors is an integer number (382957159137).

Almost surely, 2^{1422412305353} is an apocalyptic number.

1422412305353 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1422412305353 is a deficient number, since it is larger than the sum of its proper divisors (109416331195).

1422412305353 is a wasteful number, since it uses less digits than its factorization.

1422412305353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109416331194.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 1422412305353 its reverse (3535032142241), we get a palindrome (4957444447594).

The spelling of 1422412305353 in words is "one trillion, four hundred twenty-two billion, four hundred twelve million, three hundred five thousand, three hundred fifty-three".