142244333340121 has 4 divisors (see below), whose sum is σ = 142250763065872. Its totient is φ = 142237903614372.

The previous prime is 142244333340107. The next prime is 142244333340169. The reversal of 142244333340121 is 121043333442241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142244333340121 - 2⁵ = 142244333340089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142244333340821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3214829691 + ... + 3214873936.

It is an arithmetic number, because the mean of its divisors is an integer number (35562690766468).

Almost surely, 2^{142244333340121} is an apocalyptic number.

It is an amenable number.

142244333340121 is a deficient number, since it is larger than the sum of its proper divisors (6429725751).

142244333340121 is an equidigital number, since it uses as much as digits as its factorization.

142244333340121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6429725750.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 142244333340121 its reverse (121043333442241), we get a palindrome (263287666782362).

The spelling of 142244333340121 in words is "one hundred forty-two trillion, two hundred forty-four billion, three hundred thirty-three million, three hundred forty thousand, one hundred twenty-one".