1422460331041 has 4 divisors (see below), whose sum is σ = 1427034158784. Its totient is φ = 1417886503300.

The previous prime is 1422460330961. The next prime is 1422460331051. The reversal of 1422460331041 is 1401330642241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1422460331041 - 2¹³ = 1422460322849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1422460330994 and 1422460331012.

It is not an unprimeable number, because it can be changed into a prime (1422460331051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2286913405 + ... + 2286914026.

It is an arithmetic number, because the mean of its divisors is an integer number (356758539696).

Almost surely, 2^{1422460331041} is an apocalyptic number.

It is an amenable number.

1422460331041 is a deficient number, since it is larger than the sum of its proper divisors (4573827743).

1422460331041 is an equidigital number, since it uses as much as digits as its factorization.

1422460331041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4573827742.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1422460331041 its reverse (1401330642241), we get a palindrome (2823790973282).

The spelling of 1422460331041 in words is "one trillion, four hundred twenty-two billion, four hundred sixty million, three hundred thirty-one thousand, forty-one".