Base | Representation |
---|---|
bin | 1100111100010111010110… |
… | …1100011101100011011011 |
3 | 1212101111012212211220220211 |
4 | 3033011311230131203123 |
5 | 3331131000004210212 |
6 | 50133420144031551 |
7 | 2666112301441501 |
oct | 317056554354333 |
9 | 55344185756824 |
10 | 14231201241307 |
11 | 4597467104226 |
12 | 171a1286025b7 |
13 | 7c2cc547568b |
14 | 372b1832c671 |
15 | 19a2bd67e9a7 |
hex | cf175b1d8db |
14231201241307 has 8 divisors (see below), whose sum is σ = 14284220003840. Its totient is φ = 14178186193320.
The previous prime is 14231201241289. The next prime is 14231201241319. The reversal of 14231201241307 is 70314210213241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14231201241307 - 211 = 14231201239259 is a prime.
It is a super-3 number, since 3×142312012413073 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14231201241337) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6869794 + ... + 8698072.
It is an arithmetic number, because the mean of its divisors is an integer number (1785527500480).
Almost surely, 214231201241307 is an apocalyptic number.
14231201241307 is a deficient number, since it is larger than the sum of its proper divisors (53018762533).
14231201241307 is a wasteful number, since it uses less digits than its factorization.
14231201241307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1857273.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 14231201241307 its reverse (70314210213241), we get a palindrome (84545411454548).
The spelling of 14231201241307 in words is "fourteen trillion, two hundred thirty-one billion, two hundred one million, two hundred forty-one thousand, three hundred seven".
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