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14231212041 = 34743737347
BaseRepresentation
bin11010100000011111…
…10001000000001001
31100201210112110212110
431100033301000021
5213121142241131
610312052132533
71012443210054
oct152017610011
940653473773
1014231212041
11604316a272
122912007149
13145a4a3a37
149900a1a9b
155845a5646
hex3503f1009

14231212041 has 4 divisors (see below), whose sum is σ = 18974949392. Its totient is φ = 9487474692.

The previous prime is 14231212019. The next prime is 14231212043. The reversal of 14231212041 is 14021213241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14231212041 - 210 = 14231211017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14231211999 and 14231212017.

It is not an unprimeable number, because it can be changed into a prime (14231212043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2371868671 + ... + 2371868676.

It is an arithmetic number, because the mean of its divisors is an integer number (4743737348).

Almost surely, 214231212041 is an apocalyptic number.

It is an amenable number.

14231212041 is a deficient number, since it is larger than the sum of its proper divisors (4743737351).

14231212041 is an equidigital number, since it uses as much as digits as its factorization.

14231212041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4743737350.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14231212041 its reverse (14021213241), we get a palindrome (28252425282).

The spelling of 14231212041 in words is "fourteen billion, two hundred thirty-one million, two hundred twelve thousand, forty-one".

Divisors: 1 3 4743737347 14231212041