1423143331201 has 4 divisors (see below), whose sum is σ = 1426257430852. Its totient is φ = 1420029231552.

The previous prime is 1423143331171. The next prime is 1423143331231. The reversal of 1423143331201 is 1021333413241.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1423143331171) and next prime (1423143331231).

It can be written as a sum of positive squares in 2 ways, for example, as 787081254976 + 636062076225 = 887176^2 + 797535^2 .

It is a cyclic number.

It is not a de Polignac number, because 1423143331201 - 2¹⁵ = 1423143298433 is a prime.

It is a super-2 number, since 2×1423143331201² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1423143331201.

It is not an unprimeable number, because it can be changed into a prime (1423143331231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1557049140 + ... + 1557050053.

It is an arithmetic number, because the mean of its divisors is an integer number (356564357713).

Almost surely, 2^{1423143331201} is an apocalyptic number.

It is an amenable number.

1423143331201 is a deficient number, since it is larger than the sum of its proper divisors (3114099651).

1423143331201 is an equidigital number, since it uses as much as digits as its factorization.

1423143331201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3114099650.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1423143331201 its reverse (1021333413241), we get a palindrome (2444476744442).

The spelling of 1423143331201 in words is "one trillion, four hundred twenty-three billion, one hundred forty-three million, three hundred thirty-one thousand, two hundred one".