142323335435113 has 4 divisors (see below), whose sum is σ = 162655240497280. Its totient is φ = 121991430372948.

The previous prime is 142323335435063. The next prime is 142323335435159. The reversal of 142323335435113 is 311534533323241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142323335435113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 142323335435113.

It is not an unprimeable number, because it can be changed into a prime (142323335433113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10165952531073 + ... + 10165952531086.

It is an arithmetic number, because the mean of its divisors is an integer number (40663810124320).

Almost surely, 2^{142323335435113} is an apocalyptic number.

It is an amenable number.

142323335435113 is a deficient number, since it is larger than the sum of its proper divisors (20331905062167).

142323335435113 is an equidigital number, since it uses as much as digits as its factorization.

142323335435113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20331905062166.

The product of its digits is 1166400, while the sum is 43.

Adding to 142323335435113 its reverse (311534533323241), we get a palindrome (453857868758354).

The spelling of 142323335435113 in words is "one hundred forty-two trillion, three hundred twenty-three billion, three hundred thirty-five million, four hundred thirty-five thousand, one hundred thirteen".