Base | Representation |
---|---|
bin | 1100111100011011111010… |
… | …1001100000001010110011 |
3 | 1212101121101011221120211111 |
4 | 3033012332221200022303 |
5 | 3331141001322433410 |
6 | 50134141425454151 |
7 | 2666154523104163 |
oct | 317067651401263 |
9 | 55347334846744 |
10 | 14232425202355 |
11 | 4597a34a96288 |
12 | 171a40a4a1357 |
13 | 7c315bc09199 |
14 | 372bd2ad85a3 |
15 | 19a340d4eb8a |
hex | cf1bea602b3 |
14232425202355 has 4 divisors (see below), whose sum is σ = 17078910242832. Its totient is φ = 11385940161880.
The previous prime is 14232425202301. The next prime is 14232425202367. The reversal of 14232425202355 is 55320252423241.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14232425202355 - 215 = 14232425169587 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1423242520231 + ... + 1423242520240.
It is an arithmetic number, because the mean of its divisors is an integer number (4269727560708).
Almost surely, 214232425202355 is an apocalyptic number.
14232425202355 is a deficient number, since it is larger than the sum of its proper divisors (2846485040477).
14232425202355 is an equidigital number, since it uses as much as digits as its factorization.
14232425202355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2846485040476.
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 14232425202355 its reverse (55320252423241), we get a palindrome (69552677625596).
The spelling of 14232425202355 in words is "fourteen trillion, two hundred thirty-two billion, four hundred twenty-five million, two hundred two thousand, three hundred fifty-five".
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