Base | Representation |
---|---|
bin | 100000010111000111011011… |
… | …100101100001100000000011 |
3 | 200122221020022201110100002012 |
4 | 200113013123211201200003 |
5 | 122123332134411200103 |
6 | 1222411400244043135 |
7 | 41656500224306465 |
oct | 4027073345414003 |
9 | 618836281410065 |
10 | 142326015334403 |
11 | 4139314025209a |
12 | 13b6789a6934ab |
13 | 6155393785964 |
14 | 272088a046135 |
15 | 116c35da5a2d8 |
hex | 8171db961803 |
142326015334403 has 6 divisors (see below), whose sum is σ = 150211113137244. Its totient is φ = 134835172421724.
The previous prime is 142326015334381. The next prime is 142326015334423. The reversal of 142326015334403 is 304433510623241.
It is not a de Polignac number, because 142326015334403 - 224 = 142325998557187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142326015334423) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 197127444701 + ... + 197127445422.
It is an arithmetic number, because the mean of its divisors is an integer number (25035185522874).
Almost surely, 2142326015334403 is an apocalyptic number.
142326015334403 is a deficient number, since it is larger than the sum of its proper divisors (7885097802841).
142326015334403 is an equidigital number, since it uses as much as digits as its factorization.
142326015334403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 394254890161 (or 394254890142 counting only the distinct ones).
The product of its (nonzero) digits is 622080, while the sum is 41.
Adding to 142326015334403 its reverse (304433510623241), we get a palindrome (446759525957644).
The spelling of 142326015334403 in words is "one hundred forty-two trillion, three hundred twenty-six billion, fifteen million, three hundred thirty-four thousand, four hundred three".
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