Base | Representation |
---|---|
bin | 1100111100100001110100… |
… | …1011110000111111001011 |
3 | 1212101202110201100202210222 |
4 | 3033020131023300333023 |
5 | 3331202223334224233 |
6 | 50135003044100255 |
7 | 2666242032162566 |
oct | 317103513607713 |
9 | 55352421322728 |
10 | 14234011242443 |
11 | 45986792a2713 |
12 | 171a79169468b |
13 | 7c3352694b45 |
14 | 372d035d74dd |
15 | 19a3d51e2898 |
hex | cf21d2f0fcb |
14234011242443 has 4 divisors (see below), whose sum is σ = 14234130007848. Its totient is φ = 14233892477040.
The previous prime is 14234011242427. The next prime is 14234011242463. The reversal of 14234011242443 is 34424211043241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14234011242443 - 24 = 14234011242427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14234011242463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59202746 + ... + 59442687.
It is an arithmetic number, because the mean of its divisors is an integer number (3558532501962).
Almost surely, 214234011242443 is an apocalyptic number.
14234011242443 is a deficient number, since it is larger than the sum of its proper divisors (118765405).
14234011242443 is a wasteful number, since it uses less digits than its factorization.
14234011242443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118765404.
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 14234011242443 its reverse (34424211043241), we get a palindrome (48658222285684).
The spelling of 14234011242443 in words is "fourteen trillion, two hundred thirty-four billion, eleven million, two hundred forty-two thousand, four hundred forty-three".
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