142340433134131 has 4 divisors (see below), whose sum is σ = 142359801822000. Its totient is φ = 142321064446264.

The previous prime is 142340433134071. The next prime is 142340433134183. The reversal of 142340433134131 is 131431334043241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142340433134131 - 2¹¹ = 142340433132083 is a prime.

It is a super-2 number, since 2×142340433134131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142340433134191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9684332911 + ... + 9684347608.

It is an arithmetic number, because the mean of its divisors is an integer number (35589950455500).

Almost surely, 2^{142340433134131} is an apocalyptic number.

142340433134131 is a deficient number, since it is larger than the sum of its proper divisors (19368687869).

142340433134131 is an equidigital number, since it uses as much as digits as its factorization.

142340433134131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19368687868.

The product of its (nonzero) digits is 124416, while the sum is 37.

Adding to 142340433134131 its reverse (131431334043241), we get a palindrome (273771767177372).

The spelling of 142340433134131 in words is "one hundred forty-two trillion, three hundred forty billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred thirty-one".