Base | Representation |
---|---|
bin | 11010100000110111… |
… | …01101011111101011 |
3 | 1100202000102120021211 |
4 | 31100123231133223 |
5 | 213122442442103 |
6 | 10312243213551 |
7 | 1012511631310 |
oct | 152033553753 |
9 | 40660376254 |
10 | 14234343403 |
11 | 6044a08975 |
12 | 29130772b7 |
13 | 145b02c107 |
14 | 990678d07 |
15 | 5849c336d |
hex | 3506ed7eb |
14234343403 has 4 divisors (see below), whose sum is σ = 16267821040. Its totient is φ = 12200865768.
The previous prime is 14234343367. The next prime is 14234343421. The reversal of 14234343403 is 30434343241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30434343241 = 19 ⋅1601807539.
It is not a de Polignac number, because 14234343403 - 221 = 14232246251 is a prime.
It is a super-2 number, since 2×142343434032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14234343103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1016738808 + ... + 1016738821.
It is an arithmetic number, because the mean of its divisors is an integer number (4066955260).
Almost surely, 214234343403 is an apocalyptic number.
14234343403 is a deficient number, since it is larger than the sum of its proper divisors (2033477637).
14234343403 is an equidigital number, since it uses as much as digits as its factorization.
14234343403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2033477636.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 14234343403 its reverse (30434343241), we get a palindrome (44668686644).
The spelling of 14234343403 in words is "fourteen billion, two hundred thirty-four million, three hundred forty-three thousand, four hundred three".
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