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142353444001 = 811175528291
BaseRepresentation
bin1000010010010011101…
…1010010110010100001
3111121102212010012222211
42010210323102302201
54313014440202001
6145221332202121
713166436211036
oct2044473226241
9447385105884
10142353444001
115540a89848a
1223709a69341
131056832a002
146c6600d38d
153a8264d351
hex2124ed2ca1

142353444001 has 4 divisors (see below), whose sum is σ = 142528973104. Its totient is φ = 142177914900.

The previous prime is 142353443989. The next prime is 142353444029. The reversal of 142353444001 is 100444353241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142353444001 - 27 = 142353443873 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142353447001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87763335 + ... + 87764956.

It is an arithmetic number, because the mean of its divisors is an integer number (35632243276).

Almost surely, 2142353444001 is an apocalyptic number.

It is an amenable number.

142353444001 is a deficient number, since it is larger than the sum of its proper divisors (175529103).

142353444001 is an equidigital number, since it uses as much as digits as its factorization.

142353444001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175529102.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 142353444001 its reverse (100444353241), we get a palindrome (242797797242).

The spelling of 142353444001 in words is "one hundred forty-two billion, three hundred fifty-three million, four hundred forty-four thousand, one".

Divisors: 1 811 175528291 142353444001