Base | Representation |
---|---|
bin | 1000010010011110111… |
… | …0100010101101110011 |
3 | 111121120010112111210112 |
4 | 2010213232202231303 |
5 | 4313114002324021 |
6 | 145230131251535 |
7 | 13200546465164 |
oct | 2044756425563 |
9 | 447503474715 |
10 | 142400433011 |
11 | 55434371a81 |
12 | 23721749bab |
13 | 10574c9ca65 |
14 | 6c6c36176b |
15 | 3a86830d5b |
hex | 2127ba2b73 |
142400433011 has 8 divisors (see below), whose sum is σ = 150736626480. Its totient is φ = 134292628512.
The previous prime is 142400432983. The next prime is 142400433053. The reversal of 142400433011 is 110334004241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 142400433011 - 234 = 125220563827 is a prime.
It is a super-2 number, since 2×1424004330112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142400433211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57095960 + ... + 57098453.
It is an arithmetic number, because the mean of its divisors is an integer number (18842078310).
Almost surely, 2142400433011 is an apocalyptic number.
142400433011 is a deficient number, since it is larger than the sum of its proper divisors (8336193469).
142400433011 is a wasteful number, since it uses less digits than its factorization.
142400433011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114194485.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 142400433011 its reverse (110334004241), we get a palindrome (252734437252).
The spelling of 142400433011 in words is "one hundred forty-two billion, four hundred million, four hundred thirty-three thousand, eleven".
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