Base | Representation |
---|---|
bin | 11010100001101100… |
… | …11011001100010011 |
3 | 1100202111121100111020 |
4 | 31100312123030103 |
5 | 213131241040243 |
6 | 10313053250523 |
7 | 1012625306061 |
oct | 152066331423 |
9 | 40674540436 |
10 | 14241346323 |
11 | 6048961306 |
12 | 2915493a43 |
13 | 145c611759 |
14 | 99157d031 |
15 | 585408283 |
hex | 350d9b313 |
14241346323 has 4 divisors (see below), whose sum is σ = 18988461768. Its totient is φ = 9494230880.
The previous prime is 14241346319. The next prime is 14241346337. The reversal of 14241346323 is 32364314241.
14241346323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14241346323 - 22 = 14241346319 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14241346313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2373557718 + ... + 2373557723.
It is an arithmetic number, because the mean of its divisors is an integer number (4747115442).
Almost surely, 214241346323 is an apocalyptic number.
14241346323 is a deficient number, since it is larger than the sum of its proper divisors (4747115445).
14241346323 is an equidigital number, since it uses as much as digits as its factorization.
14241346323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4747115444.
The product of its digits is 41472, while the sum is 33.
The spelling of 14241346323 in words is "fourteen billion, two hundred forty-one million, three hundred forty-six thousand, three hundred twenty-three".
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