142421613250651 has 4 divisors (see below), whose sum is σ = 162767558000752. Its totient is φ = 122075668500552.

The previous prime is 142421613250627. The next prime is 142421613250663. The reversal of 142421613250651 is 156052316124241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142421613250651 - 2⁵ = 142421613250619 is a prime.

It is a super-3 number, since 3×142421613250651³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142421613250598 and 142421613250607.

It is not an unprimeable number, because it can be changed into a prime (142421613250451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10172972375040 + ... + 10172972375053.

It is an arithmetic number, because the mean of its divisors is an integer number (40691889500188).

Almost surely, 2^{142421613250651} is an apocalyptic number.

142421613250651 is a deficient number, since it is larger than the sum of its proper divisors (20345944750101).

142421613250651 is an equidigital number, since it uses as much as digits as its factorization.

142421613250651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20345944750100.

The product of its (nonzero) digits is 345600, while the sum is 43.

Adding to 142421613250651 its reverse (156052316124241), we get a palindrome (298473929374892).

The spelling of 142421613250651 in words is "one hundred forty-two trillion, four hundred twenty-one billion, six hundred thirteen million, two hundred fifty thousand, six hundred fifty-one".