Base | Representation |
---|---|
bin | 100000011000100011000011… |
… | …111001101011101000111001 |
3 | 200200021122021110201122100210 |
4 | 200120203003321223220321 |
5 | 122131440133431312213 |
6 | 1222524511144221333 |
7 | 41666552313056424 |
oct | 4030430371535071 |
9 | 620248243648323 |
10 | 142424402213433 |
11 | 4142093906456a |
12 | 13b8297816a849 |
13 | 6161743017342 |
14 | 2725540b589bb |
15 | 116ebbb3530c3 |
hex | 8188c3e6ba39 |
142424402213433 has 16 divisors (see below), whose sum is σ = 191277616803840. Its totient is φ = 94260481925136.
The previous prime is 142424402213393. The next prime is 142424402213453. The reversal of 142424402213433 is 334312204424241.
It is not a de Polignac number, because 142424402213433 - 212 = 142424402209337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142424402213391 and 142424402213400.
It is not an unprimeable number, because it can be changed into a prime (142424402213453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4389285 + ... + 17438882.
It is an arithmetic number, because the mean of its divisors is an integer number (11954851050240).
Almost surely, 2142424402213433 is an apocalyptic number.
It is an amenable number.
142424402213433 is a deficient number, since it is larger than the sum of its proper divisors (48853214590407).
142424402213433 is a wasteful number, since it uses less digits than its factorization.
142424402213433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21843956.
The product of its (nonzero) digits is 442368, while the sum is 39.
Adding to 142424402213433 its reverse (334312204424241), we get a palindrome (476736606637674).
The spelling of 142424402213433 in words is "one hundred forty-two trillion, four hundred twenty-four billion, four hundred two million, two hundred thirteen thousand, four hundred thirty-three".
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