14243034120401 has 4 divisors (see below), whose sum is σ = 14322604143600. Its totient is φ = 14163464097204.

The previous prime is 14243034120397. The next prime is 14243034120433. The reversal of 14243034120401 is 10402143034241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14243034120401 - 2² = 14243034120397 is a prime.

It is a super-3 number, since 3×14243034120401³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14243034120451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39785011331 + ... + 39785011688.

It is an arithmetic number, because the mean of its divisors is an integer number (3580651035900).

Almost surely, 2^{14243034120401} is an apocalyptic number.

It is an amenable number.

14243034120401 is a deficient number, since it is larger than the sum of its proper divisors (79570023199).

14243034120401 is an equidigital number, since it uses as much as digits as its factorization.

14243034120401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79570023198.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 14243034120401 its reverse (10402143034241), we get a palindrome (24645177154642).

The spelling of 14243034120401 in words is "fourteen trillion, two hundred forty-three billion, thirty-four million, one hundred twenty thousand, four hundred one".