142433011121 has 4 divisors (see below), whose sum is σ = 145906987044. Its totient is φ = 138959035200.

The previous prime is 142433011103. The next prime is 142433011151. The reversal of 142433011121 is 121110334241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 67060799521 + 75372211600 = 258961^2 + 274540^2 .

It is a cyclic number.

It is not a de Polignac number, because 142433011121 - 2⁶ = 142433011057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142433011151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1736987900 + ... + 1736987981.

It is an arithmetic number, because the mean of its divisors is an integer number (36476746761).

Almost surely, 2^142433011121 is an apocalyptic number.

It is an amenable number.

142433011121 is a deficient number, since it is larger than the sum of its proper divisors (3473975923).

142433011121 is an equidigital number, since it uses as much as digits as its factorization.

142433011121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3473975922.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 142433011121 its reverse (121110334241), we get a palindrome (263543345362).

The spelling of 142433011121 in words is "one hundred forty-two billion, four hundred thirty-three million, eleven thousand, one hundred twenty-one".