Base | Representation |
---|---|
bin | 11010100001111011… |
… | …11011011110010011 |
3 | 1100202122022022000200 |
4 | 31100331323132103 |
5 | 213132242013210 |
6 | 10313203350243 |
7 | 1012651111332 |
oct | 152075733623 |
9 | 40678268020 |
10 | 14243313555 |
11 | 6049a85319 |
12 | 2916082383 |
13 | 145cb4ccb3 |
14 | 991931d19 |
15 | 5856960c0 |
hex | 350f7b793 |
14243313555 has 12 divisors (see below), whose sum is σ = 24688410240. Its totient is φ = 7596433872.
The previous prime is 14243313529. The next prime is 14243313583. The reversal of 14243313555 is 55531334241.
14243313555 is a `hidden beast` number, since 1 + 42 + 433 + 135 + 55 = 666.
It is not a de Polignac number, because 14243313555 - 29 = 14243313043 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 158258995 + ... + 158259084.
It is an arithmetic number, because the mean of its divisors is an integer number (2057367520).
Almost surely, 214243313555 is an apocalyptic number.
14243313555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14243313555 is a deficient number, since it is larger than the sum of its proper divisors (10445096685).
14243313555 is a wasteful number, since it uses less digits than its factorization.
14243313555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 316518090 (or 316518087 counting only the distinct ones).
The product of its digits is 108000, while the sum is 36.
Adding to 14243313555 its reverse (55531334241), we get a palindrome (69774647796).
The spelling of 14243313555 in words is "fourteen billion, two hundred forty-three million, three hundred thirteen thousand, five hundred fifty-five".
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