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1424332344451 = 23423491462313
BaseRepresentation
bin10100101110100000110…
…100101100110010000011
312001011110011120222001111
4110232200310230302003
5141314013040010301
63010155041144151
7204622166111542
oct24564064546203
95034404528044
101424332344451
114aa068526875
121b006602b057
13a4410a17123
144cd1c038159
15270b43ed551
hex14ba0d2cc83

1424332344451 has 8 divisors (see below), whose sum is σ = 1486295949600. Its totient is φ = 1362371748672.

The previous prime is 1424332344437. The next prime is 1424332344481. The reversal of 1424332344451 is 1544432334241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1424332344451 - 25 = 1424332344419 is a prime.

It is a super-2 number, since 2×14243323444512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1424332344431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 242871 + ... + 1705183.

It is an arithmetic number, because the mean of its divisors is an integer number (185786993700).

Almost surely, 21424332344451 is an apocalyptic number.

1424332344451 is a deficient number, since it is larger than the sum of its proper divisors (61963605149).

1424332344451 is a wasteful number, since it uses less digits than its factorization.

1424332344451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1504685.

The product of its digits is 552960, while the sum is 40.

Adding to 1424332344451 its reverse (1544432334241), we get a palindrome (2968764678692).

The spelling of 1424332344451 in words is "one trillion, four hundred twenty-four billion, three hundred thirty-two million, three hundred forty-four thousand, four hundred fifty-one".

Divisors: 1 23 42349 974027 1462313 33633199 61927493237 1424332344451