Base | Representation |
---|---|
bin | 1100111101000100100100… |
… | …1111011100101110010001 |
3 | 1212102122112212201000221220 |
4 | 3033101021033130232101 |
5 | 3331330330111340423 |
6 | 50143144503035253 |
7 | 3000022152203223 |
oct | 317211117345621 |
9 | 55378485630856 |
10 | 14243340340113 |
11 | 45a1626331895 |
12 | 1720555a3bb29 |
13 | 7c41ab390291 |
14 | 37354a5d8413 |
15 | 19a77e2299e3 |
hex | cf4493dcb91 |
14243340340113 has 16 divisors (see below), whose sum is σ = 19351422330240. Its totient is φ = 9317100847104.
The previous prime is 14243340340109. The next prime is 14243340340133. The reversal of 14243340340113 is 31104304334241.
It is not a de Polignac number, because 14243340340113 - 22 = 14243340340109 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14243340340133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 211411056 + ... + 211478417.
It is an arithmetic number, because the mean of its divisors is an integer number (1209463895640).
Almost surely, 214243340340113 is an apocalyptic number.
It is an amenable number.
14243340340113 is a deficient number, since it is larger than the sum of its proper divisors (5108081990127).
14243340340113 is a wasteful number, since it uses less digits than its factorization.
14243340340113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 422889688.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 14243340340113 its reverse (31104304334241), we get a palindrome (45347644674354).
The spelling of 14243340340113 in words is "fourteen trillion, two hundred forty-three billion, three hundred forty million, three hundred forty thousand, one hundred thirteen".
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