Base | Representation |
---|---|
bin | 1100111101000100110011… |
… | …1011000011101010010011 |
3 | 1212102122201011220221022122 |
4 | 3033101030323003222103 |
5 | 3331330441414302233 |
6 | 50143154550524455 |
7 | 3000023532163232 |
oct | 317211473035223 |
9 | 55378634827278 |
10 | 14243402103443 |
11 | 45a1658187567 |
12 | 172057266672b |
13 | 7c41bb106a26 |
14 | 3735548b4b19 |
15 | 19a784879d98 |
hex | cf44cec3a93 |
14243402103443 has 4 divisors (see below), whose sum is σ = 14245602542808. Its totient is φ = 14241201664080.
The previous prime is 14243402103433. The next prime is 14243402103449. The reversal of 14243402103443 is 34430120434241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14243402103443 - 224 = 14243385326227 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14243402103449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100209973 + ... + 1100222918.
It is an arithmetic number, because the mean of its divisors is an integer number (3561400635702).
Almost surely, 214243402103443 is an apocalyptic number.
14243402103443 is a deficient number, since it is larger than the sum of its proper divisors (2200439365).
14243402103443 is an equidigital number, since it uses as much as digits as its factorization.
14243402103443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2200439364.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 14243402103443 its reverse (34430120434241), we get a palindrome (48673522537684).
The spelling of 14243402103443 in words is "fourteen trillion, two hundred forty-three billion, four hundred two million, one hundred three thousand, four hundred forty-three".
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