14243440130113 has 4 divisors (see below), whose sum is σ = 14415047842608. Its totient is φ = 14071832417620.

The previous prime is 14243440130107. The next prime is 14243440130159. The reversal of 14243440130113 is 31103104434241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14243440130113 - 2²¹ = 14243438032961 is a prime.

It is a super-2 number, since 2×14243440130113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14243440130713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85803856123 + ... + 85803856288.

It is an arithmetic number, because the mean of its divisors is an integer number (3603761960652).

Almost surely, 2^{14243440130113} is an apocalyptic number.

It is an amenable number.

14243440130113 is a deficient number, since it is larger than the sum of its proper divisors (171607712495).

14243440130113 is an equidigital number, since it uses as much as digits as its factorization.

14243440130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171607712494.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 14243440130113 its reverse (31103104434241), we get a palindrome (45346544564354).

The spelling of 14243440130113 in words is "fourteen trillion, two hundred forty-three billion, four hundred forty million, one hundred thirty thousand, one hundred thirteen".