1424350205041 has 4 divisors (see below), whose sum is σ = 1448491734000. Its totient is φ = 1400208676084.

The previous prime is 1424350205029. The next prime is 1424350205119. The reversal of 1424350205041 is 1405020534241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1424350205041 - 2¹¹ = 1424350202993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1424350204994 and 1424350205012.

It is not an unprimeable number, because it can be changed into a prime (1424350205741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12070764391 + ... + 12070764508.

It is an arithmetic number, because the mean of its divisors is an integer number (362122933500).

Almost surely, 2^{1424350205041} is an apocalyptic number.

It is an amenable number.

1424350205041 is a deficient number, since it is larger than the sum of its proper divisors (24141528959).

1424350205041 is an equidigital number, since it uses as much as digits as its factorization.

1424350205041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24141528958.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 1424350205041 its reverse (1405020534241), we get a palindrome (2829370739282).

The spelling of 1424350205041 in words is "one trillion, four hundred twenty-four billion, three hundred fifty million, two hundred five thousand, forty-one".