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14244103204035 = 352621362307089
BaseRepresentation
bin1100111101000111011010…
…1101100010110011000011
31212102201112001011112112020
43033101312231202303003
53331333410410012120
650143352313532523
73000050104350255
oct317216655426303
955381461145466
1014244103204035
1145a1987a08841
121720729414143
137c42a0440053
143735bda57cd5
1519a7c61b8640
hexcf476b62cc3

14244103204035 has 16 divisors (see below), whose sum is σ = 22799260559520. Its totient is φ = 7593956564480.

The previous prime is 14244103204007. The next prime is 14244103204109. The reversal of 14244103204035 is 53040230144241.

It is not a de Polignac number, because 14244103204035 - 25 = 14244103204003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14244103203987 and 14244103204005.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 181114230 + ... + 181192859.

It is an arithmetic number, because the mean of its divisors is an integer number (1424953784970).

Almost surely, 214244103204035 is an apocalyptic number.

14244103204035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14244103204035 is a deficient number, since it is larger than the sum of its proper divisors (8555157355485).

14244103204035 is a wasteful number, since it uses less digits than its factorization.

14244103204035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 362309718.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 14244103204035 its reverse (53040230144241), we get a palindrome (67284333348276).

The spelling of 14244103204035 in words is "fourteen trillion, two hundred forty-four billion, one hundred three million, two hundred four thousand, thirty-five".

Divisors: 1 3 5 15 2621 7863 13105 39315 362307089 1086921267 1811535445 5434606335 949606880269 2848820640807 4748034401345 14244103204035