Base | Representation |
---|---|
bin | 10100101110100110000… |
… | …111110100101000010011 |
3 | 12001011200100212111111120 |
4 | 110232212013310220103 |
5 | 141314203314242121 |
6 | 3010211534413323 |
7 | 204624325540305 |
oct | 24564607645023 |
9 | 5034610774446 |
10 | 1424421243411 |
11 | 4aa103725991 |
12 | 1b008b961243 |
13 | a4426271b6a |
14 | 4cd29b79975 |
15 | 270bc10dbc6 |
hex | 14ba61f4a13 |
1424421243411 has 4 divisors (see below), whose sum is σ = 1899228324552. Its totient is φ = 949614162272.
The previous prime is 1424421243379. The next prime is 1424421243523. The reversal of 1424421243411 is 1143421244241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1424421243411 - 25 = 1424421243379 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1424421243211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 237403540566 + ... + 237403540571.
It is an arithmetic number, because the mean of its divisors is an integer number (474807081138).
Almost surely, 21424421243411 is an apocalyptic number.
1424421243411 is a deficient number, since it is larger than the sum of its proper divisors (474807081141).
1424421243411 is an equidigital number, since it uses as much as digits as its factorization.
1424421243411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 474807081140.
The product of its digits is 24576, while the sum is 33.
Adding to 1424421243411 its reverse (1143421244241), we get a palindrome (2567842487652).
The spelling of 1424421243411 in words is "one trillion, four hundred twenty-four billion, four hundred twenty-one million, two hundred forty-three thousand, four hundred eleven".
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