1424421324121 has 4 divisors (see below), whose sum is σ = 1445681343952. Its totient is φ = 1403161304292.

The previous prime is 1424421324107. The next prime is 1424421324133. The reversal of 1424421324121 is 1214231244241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1424421324121 - 2⁹ = 1424421323609 is a prime.

It is a super-2 number, since 2×1424421324121² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1424421324181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10630009815 + ... + 10630009948.

It is an arithmetic number, because the mean of its divisors is an integer number (361420335988).

Almost surely, 2^{1424421324121} is an apocalyptic number.

It is an amenable number.

1424421324121 is a deficient number, since it is larger than the sum of its proper divisors (21260019831).

1424421324121 is an equidigital number, since it uses as much as digits as its factorization.

1424421324121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21260019830.

The product of its digits is 12288, while the sum is 31.

Adding to 1424421324121 its reverse (1214231244241), we get a palindrome (2638652568362).

The spelling of 1424421324121 in words is "one trillion, four hundred twenty-four billion, four hundred twenty-one million, three hundred twenty-four thousand, one hundred twenty-one".