142442503135241 has 4 divisors (see below), whose sum is σ = 143010003147984. Its totient is φ = 141875003122500.

The previous prime is 142442503135111. The next prime is 142442503135327. The reversal of 142442503135241 is 142531305244241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142442503135241 is a prime.

It is a super-2 number, since 2×142442503135241² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (142442503135841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 283750005995 + ... + 283750006496.

It is an arithmetic number, because the mean of its divisors is an integer number (35752500786996).

Almost surely, 2^{142442503135241} is an apocalyptic number.

It is an amenable number.

142442503135241 is a deficient number, since it is larger than the sum of its proper divisors (567500012743).

142442503135241 is an equidigital number, since it uses as much as digits as its factorization.

142442503135241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 567500012742.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 142442503135241 its reverse (142531305244241), we get a palindrome (284973808379482).

The spelling of 142442503135241 in words is "one hundred forty-two trillion, four hundred forty-two billion, five hundred three million, one hundred thirty-five thousand, two hundred forty-one".